Practice Test | Kullabs.com
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  • The equation of a straight line having Slope = -1 and y-intercept = 5 is ______.

    x + y = 5 
    x + y - 5 = 0
    x - y + 5 = 1
    x + y = 0
  • Find the equation of straight line when Slope = (frac{3}{5}) and y-intercept = (frac{4}{7}) units.

    30x + 3y + 27 = 0
    25x + y -10 = 0 
    20x - 5y = 0 
    21x - 35y + 20 = 0
  • Find the equation of straight line if Inclination (θ) = 30° and y-intercept = 4 units.

    7x + (sqrt{y}) - 3= 0
    (sqrt{x}) - (sqrt{3y}) = 0
    x - (sqrt{3})y + 4(sqrt{3}) = 0 
    3x + y (sqrt{12}) = 0  
  • Find the equation of a straight line whose X-intercept (a) = 5 and y-intercept (b) = 6.

    6x + 5y - 30 = 0 
    3y + y = 0
    7x + 6yn - 10 = 0
    x - 2y + 9 = 0
  • Find the equation of a straight line whose X-intercept (a) = -7 and Y-intercept (b) = -2.

    x - 6y = 0 
    2x + 7y - 23 = 0
    7x + 3y = 0
    2x + 7y - 14 = 0
  • Find the equation of a straight line whose X-intercept (a) = (frac{3}{5}) and Y-intercept (b) = (frac{6}{5}).

     10x + 5y - 6 = 0 
    9x - y + 21 = 0 
    12x + 3y - 9 = 0  
    8x - 6y - 19 = 0  
  • Find the equation of straight line whose X-intercept (a) = (frac{2}{3}) and Y-intercept (b) = (frac{-4}{5}).

    6x - 5y - 4 = 0
    5x + y + 2 = 0
    6x - 2y - 12 = 0 
    5x + 7yb - 12 = 0
  • Find out the equation of a straight line whose inclination is 45° and y-intercept is 2.

    2x + 2y + 2 = 0
     x - 2y + 5 = 0
    y - x - 2 = 0
    x + y - 3 = 0 
  • find the equation of a line passing through the point (0, 5) and inclined at an angle of 60° with x-axis.

    x + y - 12 = 0
    y = (sqrt{3})x + 5
    y = 3x - 5
    x = 3y - 2
  • Find the equation of a straight line whose X-intercept and Y-intercept are 3 and -4 respectively.

    2x + 3y - 7 = 0 
    6x + y + 12 = 0 
    4x - 3y - 12 = 0
    x + y - 2 = 0
  • Find the equation of straight line if Inclination (θ) = 135° and y-intercept = (frac{3}{2}) units.

    x + y + 3 = 0 
     2x + 5y - 2 = 0
    2x + 2y - 3 = 0 
    3x - 4y - 3 = 0 
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