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Ordered Pair and Cartesian Product

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As we know in mathematics order plays an important role .In some case we may feel not so important for example,{Shiva,Parvati} or {Parvati, Shiva} as both are sets of two people but here if we start thinking of a pair of gloves then right side of gloves should be usedin right and left side of glove should be used in left . If ordered of glove change than it is not comfortable at all.Hence ordered plays a vital role.

Order

An order is an arrangement of members or elements in a meaningful way is called order . Some example of order are;

(1)5,6,7,8,9

It is an order of numbers whose each next number is 1.

(2)a,b,c,d,e

This is a first five English alphabets an order.

(3)2,4,6,8,10

first five multiples of 2 in ascending order.

Pair

A pair is a combination of two objects or number . for example,a pair of gloves ,a pair of shoes ,Shiva and Parvati,Nepal and Kathmandu etc

Ordered pair

The combination of numbers or elements in a fixed order is called ordered pair.Here the first elements represent the x-component (x) and the second elements represent the y-components (y).An ordered pair are always separate by comma and closed by small brackets. For example (a, b), (1, 2), (Ram, Sita) etc.

Here in order pair the first x and the second y component should always follow the order if not then it can give different meaning .

For example ;

The ordered pair bellow is a pair which represents the nation and its capital city

(Nepal, Kathmandu)

(India, New Delhi)

But if we write (Kathmandu,Nepal), Kathmandu becomes the nation and Nepal become the capital city which is completely wrong . So we need to follow in a meaningful order here in case of set {Nepal, Kathmandu } or {Kathmandu, Nepal} both are same. but here its plays an important role.

The x and y component is known as antecedent and consequence respectively .We can also use a diagram to represent the ordered pairs.

Equality of ordered pair

The ordered pairs (e, f)and (g, h) are said to be equal if their corresponding elements are equal . i.e, the first component eshould be equal to the first components gand the second component should be equal to the second component.

Mathematically,

If ( e, f ) = ( g, h ) then

e = g and f = h

For example; Is the ordered pair equal ?

(5, 6) = (5, 6)

Hence, the ordered pair x=5 and y =6 in both.

Cartesian product

Let M and N be two non-empty sets . Then the products M * N read as M cross N is defined as the set of all ordered pairs in such a way that the first elements is taken from set M and the second element is taken from set B.

Mathematically

M ×N = {(x, y) :x∈M and y∈N}

Now , M = {1, 2} N = {a, b }

Then, M × N can be calculated as in the following table.

1

Now, M ×N in the set of all above ordered pairs and we write it as ,

M ×N = { ( 1. a), ( 1, b), ( 2,a ), (2, b) }

Again, N × M can be written as,

B

A

a b
1 (1, a) (1, b)
2 (2, a) (2, b)

So , N × M = { ( a, 1), ( a, 2 ), (b, 1), (b, 2) }

from example also it is observed that

since, (1, a ) ≠ ( a, 1 )

M * N ≠ N × M

The cartesian product can be also obtained by using an arrow diagram .

1

from this arrow diagram also we can see that

M × N = { (1, a ), (1, b ), ( 2, a ), ( 2, b ) }

Again, for N × M , we place N first and M second and draw arrows to represent it.

So, N×M = {(a, 1 ), ( a, 2 ), (b, 1 ), ( b, 2)}

figure ;



  • Order is the arrangement  of member or elements in a sequential manner  or  a meaningful way .
  • Pair is the combination of two objects or numbers.
  • For eg ; ( p , q ) and ( q , p ) are not equal ordered pairs  as in ( p, q ) the first component is p and the second component is q  and vice versa in ( q , p ).
.

Very Short Questions

Solution

(x, y) = (2, 5)

Since the ordered pairs are equal, the corresponding elements are also equal. 

So, x = 2 and y = 5

Solution

Since the ordered pairs are equal the corresponding elements are also equal. 

So,  x - 2 = 2 

      x = 2 + 2

       x = 4

Similarly,  2 = y + 1

                   y + 1 = 2 

                   y = 2 - 1 

                   y = 1

Hence, x = 4 and y = 1

Solution

Since the ordered pairs are equal the corresponding elements are also equal. 

So,  x - 7 = 5 

      x = 5 + 7

       x = 12

Similarly,  5 = y + 1

                   y + 1 = 5 

                   y = 5 - 1 

                   y = 4

Hence, x = 12 and y = 4

Solution

Since the ordered pairs are equal the corresponding elements are also equal. 

So,  x - 2 =  10

      x = 10 + 2

       x =  12

Similarly,  4 = y + 5

                   y + 5 = 4 

                   y = 4 - 5

                   y = -1

Hence, x =  12  and y =  - 1

Solution

Here, A ={3, 4} and B = {1, 2}

Now, A × B = {(3, 1) (3, 2) (4, 1) (4, 2) }.

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  •  The  arrangement of member or elements in a sequential manner or a meaningful way is known as __________________________ . 

     pair
    equality 
    an order
    ordered pair
  • The combination of the two objects or numbers is known as a _________________ . 

    order
    pair
    ordered pair
    equality
  • The elements of an ordered pair are always separated by ____________ .

    big bracket
    small brackets
    comma
    pair
  • If  P (a, b) and Q(1} find P × Q

    (a, 1) (1, b)
    (b, 1) (1, a)
    ( a, 1) (b, 1) 
    (a, b) (1, 1)
  • Find the value of x and y. 

    (x, y) = (2, 3)

    x = 2, y = 3
    x = 5, y= 1
     x= 4, y= 7 
    x= 2, y= 0
  •  Find the value of x and y. 

    (x - 2, (frac{y}{4})) = (2, 0)

     x = 1, y= 8
     x= 5, y= 0
     x = 3, y=0
     x = 4, y = 0
  • Find the value of x and y.

    (x-2, 9) = (3x - 5, y + 3)

    x = (frac{9}{2}), y = 3
     x = (frac{3}{2}), y = 6
    x = (frac{7}{2}), y = 4
    x = (frac{5}{2}), y = 5
  • Find the value of x and y.

    ( x - 1, y + 2) = (3, 6)

     x = 4, y = 4
     x = 4, y = 5
     x = 5, y= 3
     x = 3, y = 5
  • Find the unknown values of the following:

    ((frac{x}{2}), (frac{y}{3})) = (2, 3)

     x= 7, y= 5
     x = 5, y= 8
     x= 4, y = 9
     x= 6, y=8
  • If A = {1, 2}. Find A × A

    (4, 2) (1, 2) (2, 3) (1, 2)
    (1, 2) (2, 3) (2, 1) (2, 3)
    { (1, 2) (1, 1) (2, 1) (2, 2)}
    (2, 1) (4, 1) (1, 2) (1, 1) 
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