The number with base sixteen is called hexadecimal number. We can generate these numbers with the combination of 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A,B, C, D, E, F. Where A=10, B=11, C=13, D=14, E=15, F=16. We can represent these numbers with suffix sixteen. E.g. (12AB)_{16} Where A=10, B=11. The 4-bit format of binary is used for hexadecimal to binary conversion.
Weighted value
Decimal | Octal | Hexadecimal | Binary |
0 | 0 | 0 | 0000 |
1 | 1 | 1 | 0001 |
2 | 2 | 2 | 0010 |
3 | 3 | 3 | 0011 |
4 | 4 | 4 | 0100 |
5 | 5 | 5 | 0101 |
6 | 6 | 6 | 0110 |
7 | 7 | 7 | 0111 |
8 | 8 | 1000 | |
9 | 9 | 1001 | |
10 | A | 1010 | |
11 | B | 1011 | |
12 | C | 1100 | |
13 | D | 1101 | |
14 | E | 1110 | |
15 | F | 1111 |
The decimal number is repetitively divided by sixteen and remainders are collected to represent hexadecimal numbers.
Example
1. Convert following in hexadecimal number: (1047)_{10}= (417)_{16}
16 | 1047 | 7 |
16 | 65 | 1 |
4 |
=(417)_{16}
2. Convert (333)_{10} into hexadecimal
16 | 333 | 13 |
16 | 20 | 4 |
4 |
(333)_{10}= (14D)_{16} Where D=13
Each hexadecimal digit is multiplied by weighted positions, and sum of product is equal to decimal value.
Example
1. (A37E)_{16}=(?)_{10}
A= 10
E= 14
=Ax16^{3}+ 3 x 16^{2}+ 7 x 16^{1}+ E x 16^{0}
=10x16^{3}+ 3 x 16^{2}+ 7 x 16^{1}+ 14 x 16^{0}
=40960 + 768 + 112 + 14
(41852)_{10}
The binary numbers are broken into sections of 4-bit digits from last bit and its hexadecimal equivalent is assigned for each section.
Example
1. Convert (11 10 11)_{2} into base 16.
(11 10 11)_{2}= 11 1011
0011= 3
1011= 11= B
(3B)_{16}
Note: You have to add 00 before first group to make four bits group. (11 to 0011)
Binary equivalent of each hexadecimal digit is written in 4-bit format or section.
Example
Convert following in Binary numbers:
Algorithm
1. (45AF)_{16}
4= 100= 0100 (Make four digit by adding 0 before the bits)
5= 101= 0101
A=10= 1010
F= 15= 1111
=(010001011010111)_{2}
2. (23AB)_{16}= (0010 0011 1010 1011)_{2}
= 0010, 3= 0011, A= 10, B=11= 1011
=(0010 0011 1010 1011)_{2}
Example
1. (ABC)_{16} to (?)_{2}
(ABC)_{16}
A=10= 1010
B=11= 1011
C= 12= 1100
=(101010111100)_{2}
You have to learn addition, subtraction, multiplication, and division of binary number. In brain, you have to keep that in the arithmetic of binary number, carry is written in binary (2) just like as 10 is used in decimal system for carry.
Addition | Subtraction | Multiplication | Division |
0 + 0 = 0 1 = 0 = 1 | 0 - 0 = 0 1 - 0 = 1 | 0 * 0 = 0 1 * 0 = 0 | 0 · 1 = 0 1 · 0 = not defined |
Example Here, 1+1(right most)= 0 and its carry 1 is added to left columns as 1+1 = 11 Hence, 11+ 11= 110 | Example Here, 0-1 (right most) = 1 because we take carry 2 from left column and left remains 0. Hence, 10- 01 = 01 | Example | Example |
Addition Example
1 | 0 | 1 | 0 | First number | |
1 | 0 | 0 | 1 | Second number | |
1 | 0 | 0 | 1 | 1 |
Add following binary numbers
1. 1100 + 1111= 11011
1 | Carry | |||
1 | 1 | 0 | 0 | |
1 | 1 | 1 | 1 | |
11 | 0 | 1 | 1 |
2. 110011+ 111100 + 100110= 10010110
1 | 1 | 1 | 1 | 1 | Carry | |||
1 | 1 | 0 | 0 | 1 | 1 | |||
1 | 1 | 1 | 1 | 0 | 0 | |||
1 | 0 | 0 | 1 | 1 | 1 | |||
1 | 0 | 0 | 1 | 0 | 1 | 1 | 0 |
The subtraction of binary is more interesting, but less complex for novice students, but not fear, jump to complement methods when confusing takes place in the traditional methods of subtraction.
Example
110-11=011
The first step is to equalize digits placing zero to the left side and make columns. You take right most columns and solve 0-1.
1 | 1 | 0 |
0 | 1 | 1 |
1 |
Next step, come to second column from where you have to solve again 0-1.
1 | 1 | 0 |
0 | 1 | 1 |
0 | 1 | 1 |
Example
1000-11= 0101
1 | 0 | 0 | 0 |
0 | 1 | 1 | 1 |
0 | 0 | 0 | 1 |
Example
1000 -1= 111
1000 -10= 110
The multiplication of binary number is also like as decimal multiplication.
Example
110 x 11 = 10100
1 | 1 | 0 | 0 | ||
x | 1 | 1 | |||
1 | 1 | 0 | 0 | ||
1 | 1 | 0 | 0 | ||
1 | 0 | 0 | 1 | 0 | 0 |
The division process is like as division of decimal numbers.
Quotient 1 and remainder 100.
A number system that uses sixteen different digits to represent different values is known as hexadecimal number system. The base of hexadecimal number system is 16 because it consist sixteen digits from 0 to 9 and A to F to represent values from ten to fifteen. The digits A, B, C, D, E and F of hexadecimal number represent the decimal numbers 10, 11, 12, 13, 14 and 16 respectively.
The decimal equivalent of a hexadecimal number is the sum of the digits multiplied by 16 with their corresponding weights.
Convert (A2E)_{16} into Decimal
Solution:
2 1 0 (weight)
Hexadecimal Number: A 2 E
Decimal Equivalent = A×16^{2} + 2×16^{1} + E×16^{0}
= 10×256 + 2×16 + 14×1
= 2560 + 32 + 14
= 2606
Hence, (A2E)_{16} = (2606)_{10}
Hexadecimal digit is represented in 4 bits. A hexadecimal number is converted to its binary equivalent by just substituting the respective binary value for each digit of the hexadecimal number.
Convert (4A5)_{16} into Binary
Solution:
Hexadecimal Number: 4 A 5
Binary Equivalent: 100 1010 0101 (From Binary Table)
Hence, (4A5)_{16} = (10010100101)_{2}
There is no any direct method to convert hexadecimal number into octal. So, at first the given hexadecimal number is converted into its binary equivalent then the result will be converted into octal as in previous methods.
Convert (42C)_{16} into Octal
Solution:
Hexadecimal Number: 4 2 C
Binary Equivalent: 100 0010 1100 (From Binary Table)
Again, Paired Binary
For octal (3 bits): 10 000 101 100 (pairing from right-most digit)
Hexadecimal Equivalent: 2 0 5 4
Hence, (42C)_{16} = (2054)_{8}
Binary numbers are added to the same manner as decimal numbers. There are only four possible combinations resulting from the addition of two binary digits.
Rules for binary addition:
A | B | A+B |
0 | 0 | 0 |
0 | 1 | 1 |
1 | 0 | 1 |
1 | 1 | 10 |
The rules for subtraction are the same in the binary system as in the decimal system. The result of the subtraction of binary digit is either 0 or 1.
Rules for binary subtraction:
A | B | A-B |
0 | 0 | 0 |
1 | 0 | 1 |
1 | 1 | 0 |
0 | 1 | 1 |
Binary numbers are multiplied in the same manner as decimal numbers. We need to remember the rules of binary addition.
Rules for binary multiplication:
A | B | A×B |
0 | 0 | 0 |
1 | 0 | 0 |
0 | 1 | 0 |
1 | 1 | 1 |
Binary numbers are divided in the same manner as decimal numbers. We need to remember the rules of binary subtraction.
Rules for binary division:
A | B | A/B |
0 | 0 | 0 |
1 | 0 | 1 |
1 | 1 | Not defined |
0 | 1 | Not defined |
What is the binary value of the hexadecimal number 45AF?
ASK ANY QUESTION ON Hexadecimal and Binary Arithmetic
No discussion on this note yet. Be first to comment on this note