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The quinary number system is a number system having five as the base. There are only five numerals in the quinary number system. They are 0, 1, 2, 3 and 4 in this system. This will represent any real numbers.
Quinary means base 5 so each place is a power of 5.
In this method five is written as 10, twenty-five is written as 100 and sixty is written as 220.
Consider the quinary number of 155_{5 }
155_{5} = 1 x 5^{2} + 5 x5^{1} + 5 x5^{0}
= 25 + 25 + 5
= 55
While converting a decimal number into a quinary number, we must divide it by 5 repeatedly and write the remainders until the result of the division is 0. The quinary number is obtained by reading the sequence of the remainders in the reverse order. For example, let's consider the number 84_{10}
84 ÷ 5 = 16 Remainder 4
16 ÷ 5 = 3 Remainder 1
3÷ 5 = 0 Remainder 2
Finding arithmetic in a base other than 10 is to understand the notation we use in base 10.
We write the number thirteen as 13, meaning 1 tens and 3 ones. It may help you to think about objects, like sticks. The idea is to make thirteen sticks and arrange them in the group of ten. You get 1 groups of ten and three extra.
Suppose, if you add 23 and 19 you put together the 3 ones with the 9 ones giving 12 ones, which is 1 ten and 2 extra. That is you get one more group of ten sticks. That is the "carry over". So, altogether you have 2 + 1 + 1 tens and 2 ones, for a sum of 42.
In base-5, you want to collect the objects in groups of five rather than tens. So if you have nine objects you can arrange them into one group of five and 4 ones.
Now to add 2 and 3 using base 5 notation, 2 + 3 = 10 in base 5.
Subtraction in quinary number is straight forward as we are always subtracting a smaller digit from a large digit. Let's look at a base 10 problem first.
3 2 5
\(\underline{-1 3 4}\)
1 9 1
Starting in the right most column 5 - 4 = 1 but in the next column you need to borrow from the next column. Since this is base 10 notation you are borrowing ten so the 3 in the third column be 2 and adding to 10 to 2 you have 12 in the second column.
Now,
Let's try a base 5 problem
431
\(\underline{-240}\)
141
As in the base 10 problem, the first column is easy, 1 - 0 = 1. In the second you need to borrow from the third column. Since the numbers are written in base 5 notation you are borrowing five so the 4 in the third column becomes 3 and adding five to gives you eight in the second column.
Example:
Convert the following decimal number into a quinary number.
a) 425
Solution:
5 | 425 | 0 |
5 | 85 | 0 |
5 | 17 | 2 |
5 | 3 | 3 |
0 |
∴ 425_{10} = 3200_{5}
Solution:
5 | 425 | 0 |
5 | 85 | 0 |
5 | 17 | 2 |
5 | 3 | 3 |
0
∴ 425_{10} = 3200_{5}
Solution:
5 | 924 | 4 |
5 | 184 | 4 |
5 | 36 | 1 |
5 | 7 | 2 |
5 | 1 | 1 |
0 |
∴ 924_{10} = 12144_{5}
Solution:
5 | 924 | 4 |
5 | 184 | 4 |
5 | 36 | 1 |
5 | 7 | 2 |
5 | 1 | 1 |
0 |
∴ 924_{10} = 12144_{5}
Solution:
5 | 1574 | 4 |
5 | 312 | 2 |
5 | 62 | 2 |
5 | 12 | 2 |
5 | 2 | 2 |
0 |
∴ 1574_{10} = 22224_{5}
Solution:
5 | 2487 | 2 |
5 | 497 | 2 |
5 | 99 | 4 |
5 | 19 | 4 |
5 | 3 | 3 |
0 |
∴ 2487_{10} = 34422_{5}
Solution:
5 | 3040 | 0 |
5 | 608 | 3 |
5 | 121 | 1 |
5 | 24 | 4 |
5 | 4 | 4 |
0 |
∴ 3040_{10} = 44130_{5}
Solution:
5 | 5864 | 4 |
5 | 1172 | 2 |
5 | 234 | 4 |
5 | 46 | 1 |
5 | 9 | 5 |
5 | 1 | 1 |
0 |
∴ 5864_{10} = 151424_{5}
Solution:
5 | 1574 | 4 |
5 | 312 | 2 |
5 | 62 | 2 |
5 | 12 | 2 |
5 | 2 | 2 |
0 |
∴ 1574_{10} = 22224_{5}
Solution:
5 | 5864 | 4 |
5 | 1172 | 2 |
5 | 234 | 4 |
5 | 46 | 1 |
5 | 9 | 4 |
5 | 1 | 1 |
0 |
∴ 5864_{10} = 141424_{5}
Solution:
212_{5}
= 2× 5^{2} + 1× 5^{1} + 2× 5^{0}
= 2× 25 + 1× 5 + 2× 1
= 50 + 5 + 2
= 57_{10}
Solution:
2304_{5}
= 2× 5^{3} + 3× 5^{2} + 0× 4^{1} + 4× 5^{0}
= 2× 125 + 3× 25 + 0×4 + 4×1
= 250 + 75 +0 +4
= 329_{10}
Solution:
3104_{5}
= 3× 5^{3} + 1× 5^{2} + 0×5^{1} + 4× 5^{0}
= 3× 125 + 1× 25 + 0×5 + 4×1
= 375 + 25 + 0+ 4
= 404_{10}
Solution:
1110_{2}
= 1× 2^{3} + 1× 2^{2} + 1× 2^{1}+ 0×2^{0}
= 8 + 4 + 2 +0
= 14_{10}
Now,
5 | 14 | 4 |
5 | 2 | 2 |
0 |
∴ 1110_{2} = 14_{10} = 24_{5}
Solution:
1011_{2}
= 1 × 2^{3} + 0× 2^{2} + 1× 2^{1} + 1× 5^{0}
= 8 + 0 + 2 + 1
= 11_{10}
Then,
5 | 11 | 1 |
5 | 2 | 2 |
0 | ||
∴ 1011_{2} = 11_{10} = 21_{5}
Solution:
1111_{2}
= 1× 2^{3} + 1× 2^{2} + 1× 2^{1} + 1×2^{0}
= 8 + 4 + 2 + 1
= 15_{10}
Then,
5 | 15 | 0 |
5 | 3 | 3 |
0 |
∴ 1111_{2} = 15_{10} = 30_{5}
Solution:
2134_{5}
= 2× 5^{3} + 1× 5^{2} + 3× 5^{1} + 4× 5^{0}
= 250 + 25 + 15 + 4
= 294
Then,
2 | 244 | 0 |
2 | 122 | 0 |
2 | 61 | 1 |
2 | 30 | 0 |
2 | 15 | 1 |
2 | 7 | 1 |
2 | 3 | 1 |
2 | 1 | 1 |
0 |
∴ 294_{10} = 11110100_{2}
Convert the following quinary number into decimal number.
3104_{5}
Convert the following quinary number into decimal number.
1044_{5}
Convert the following quinary number into decimal number.
212_{5}
Convert the following quinary number into decimal number.
314_{5}
Convert the following quinary number into decimal number.
412_{5}
Convert the following decimal number into quinary number.
672
Convert the following decimal number into quinary number.
512
Convert the following quinary number into binary number.
121_{5}
Convert the following quinary number into binary number.
441_{5}
Convert the following quinary number into binary number.
2134_{5}
Convert the following binary number into quinary number.
110110_{2}
Convert th efollowin decimal number into quinary number.
348
Convert the following binary number into quinary number.
1101_{2}
Convert the following binary number into quinary number.
1111_{2}
4132_{5}
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SmR'u PnR!z
i know all of this before reading this.I haye comment first on it.OH!YESSS
Jan 31, 2017
1 Replies
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