Combination of Transformations

The transformations discussed above are the examples of single transformation. When an object has been transformed, its image can again be transformed to form a new image. Such transformation is called a combination of transformations. After a combination of transformations, the change from the single object to the final image can be described by a single transformation.

Let R1 be a transformation which maps a point Pto the point P' and R2 be another transformation which maps P' to the point p''. Then, the transformation which maps a point P to P'' is said to be the combination of R1 and R2 or it is said to be the composite transformation of R1 and R2. It is denoted by R2 or R1.The composite transformation R2 R1 is also called as the transformation R1 followed byR2.

The transformations R1R2 andR2R1 have different meanings. R1R2 gives a combination of transformations R2 followed by R1 whereas, R2R1 gives the combination of transformations R1 followed by R2.

If T and W are two different transformations, then the product TW gives the combination of the transformations W followed by T (this means to work out W first and then apply T), which can be denoted by single transformation say Z and we write it as Z = TW.

The composite transformation of R with itself is denoted by R .R = R2.

Combination of two translations

Combination of two translations
Combination of two translations

A translation followed by a translation is equivalent to a single translation.

Let T1 = (\()\frac{a}{b}\) be a translation vector. It describes the translation of units in the X - direction and units in the Y - direction.Let T1 translates a point P to P'.

Let T2 =(\(\frac{c}{d}\)) be another translation vector. It describes the translation ofc units in the X-direction and units in the Y-direction. Let T2 translates P' to the point P''.

Now, we want to find out the translation vector which translates the point P to P'. Then,

x - component of T = PB = PA + AB = PA + P'C = a + c

Y - component of T = BP'' = BC + CP'' = AP' + CP'' = b + d

∴ T = T2oT1 = (\(\frac{a + c}{b + d}\))

Hence, if the translation T1 = (\(\frac{a}{b}\)) is followed by the translation T2 = (\(\frac{c}{d}\)), then the composite translation T2oT1 is described by (\(\frac{a + c}{b + d}\)).

Combination of two rotations

A rotation followed by a rotation is equivalent to a single rotation

1. When two rotations are about the same centre:

A point or an object once rotated about the centre through a given angle can further be rotated about the same centre through another given angle.

Let P (x, y) be any point in the plane. If Q1 be the rotation about origin through 900, then

Q1: P (x, y)→ P' (-y, x).

Again, if Q2 be the rotation about the origin through 900, then

Q2: P'(-y, x)→ P'' (-x, -y).

Here, Q2.Q1: P (x, y)→ P''(-x, -y).

But (-x, -y) is the image of the point (x, y) under the rotation about the origin through 1800.

Hence, a rotation of x0 followed by a rotation of y0 about the same centre is equivalent to the rotation of (x0 + y0) about the same centre.

2. When two rotations are about the different centre:

 When two rotations are about the different centre
When two rotations are about the different centre

A point or an object once rotated about a centre through a given angle can further be rotated about the different centre through another given angle.

Let R1 be the rotation through an angle x0 about the centre and R2 be another rotation through an angle y0 about the different centre. Then, the equivalent transformation (R2oR1) is again a new rotation through the angle (x0 + y0) about the third centre. This centre is the meeting point of the perpendicular bisectors of the line segments joining corresponding vertices of the object and its final image. In other words, perpendicular bisectors of the line segment joining corresponding vertices of the object and its final image are concurrent and the point of concurrence is the centre of new rotation ( i.e. combined rotation).

Let ABC be the given triangle (object). It is rotated toΔ A'B'C' through 900 about the centre P. The triangle A'B'C' is again rotated to ΔA''B''C'' through 900 about the centre Q. ThenΔ A"B" C" is the image ofΔABC under the rotation through 1800 about the third centre R. Perpendicular bisectors of AA", BB", CC" intersect each other at the point R.

Combination of two reflection

A point or object once reflected can further be reflected to form a new image. The axes of these reflections may be parallel to each other or they intersect each other at a point. So, there are two cases for the combination of two reflections.

When the axes of reflections are parallel
When the axes of reflections are parallel

(1) When the axes of reflections are parallel

Let Ab and CD be parallel to each other. Let P' be the image of P under the reflection in the line AB. Then,

PM = MP' and so, PP' = 2 MP'.

Let P' be the image of P" under the reflection of the line CD. Then,

P'N = NP" and so, P'P" = 2P'N.

Here, P" is the image of P under the reflection in the line AB followed by the reflection in the line CD.

Now, \(\overrightarrow{P}{P"}\) = \(\overrightarrow{P}{P'}\) + \(\overrightarrow{P'}{P"}\) = \(\overrightarrow{M}{P'}\) + \(\overrightarrow{P'}{N}\) = 2( \(\overrightarrow{M}{P'} + \overrightarrow{P}'{N})\) = 2 \(\overrightarrow{M}{N}\)

Hence, if the axis of reflection is parallel, a reflection followed by another reflection is equivalent to the translation. The distance of the translation is twice the distance between the axes of reflections and the direction is perpendicular to the axis of reflections.

2. When the axes of reflection intersect at a point

When the axes of reflection intersect at a point
When the axes of reflection intersect at a point

Let OA and OB intersect each other at the point O. Let P" be the image of P' under the reflection in the line OB. Then, OB is the perpendicular bisector of PP'.

∴∠POM =∠POM =θ (say)

Let P" is the image of P' under the reflection in the line OB. Then, OB is the perpendicular bisector of P'P".

∴∠P'ON =∠P"ON =Φ(say)

Here, P" be the image under the reflection in the line OA followed by the reflection in the line OB.

Now,

∠POP" =∠POM +∠P'OM +∠P'ON +∠P"ON = θ+θ +Φ +Φ = 2(θ +Φ)

= 2(∠P'OM + ∠P'ON) = 2∠MON.

Hence, if the axes of reflections intersect at a point O, then a reflection followed by another reflection is equivalent to a rotation about the centre O through the angle twice the angle between the axes of reflection. The direction of rotation is the direction from OA to OB (i.e. the direction from P to P").

A reflection followed by a reflection is equivalent to either a translation or a rotation.

In the following figure, O is the point of intersection of two straight lines OP and OQ.ΔA'B'C' is the image ofΔABC under the reflection in the line OP andΔA"B" C" is the image ofΔA'B'C' under the reflection in the line OQ. In fact, ΔA"B" C" is the image ofΔABC under the rotation about O through an angle 2∠POQ.

combination of two reflection over intersecting lines
combination of two reflection over intersecting lines

In the following figure AB and CD are two parallel straight lines.ΔP'Q'R' is the image ofΔpqr under the reflection in the line AB andΔP"Q" R" is the image ofΔP'Q'R'. In factΔP"Q" R" is the image ofΔPQR under a translation whose magnitude is twice the distance between AB and CD.

combination of two reflections over two parallel lines
combination of two reflections over two parallel lines

Combination of two enlargements

An object once enlarged can further be enlarged. Similarly, an object once reduced can further be reduced.

There are two cases in the combination of two enlargements:

When the centres of enlargements are same

q

Let E1(O, k) be the enlargement with centre O and the scale factor k.

Let A'B' be the image of the given line AB under the enlargement E1 with centre o and the scale factor k.

Then, A'B' =kAB.

Let E2[O, k'] be the enlargement with centre O and scale factor k'.

Let A"B" be the image of A'B' under the enlargement E2 with centre O and scale factor k'. Then A"B" = k'A'B'.

Now,

A"B" = k'A'B' = k'k AB.

∴ A"B" is the image of AB under an enlargement E(O, kk') with centre O and scale factor kk'.

Hence, an enlargement with centre O and scale factor k followed by another enlargement with the same centre O and scale factor k' is equivalent to an enlargement with the same centre and scale factor kk'.

2. When the centres of enlargements are different

Let E1 [O, k] be the enlargement with centre O and scale factor k. Let AB be the image of AB under enlargement E1 with centre O and scale factor k.

Then, A'B' = kAB.

Let E2 [O', k'] be the enlargement with centre O' and scale factor k'.

Let A"B" be the image of A'B' under enlargement E2 with centre O' and scale factor k'.

Then, A"B" = k'A'B'.

Now, A"B" = k'A'B' = k'kAB.

Join A"A' and B"B'. The intersect each other at the point O".

So, A"B" is the image of AB under an enlargement E[O, k'k] with the third centre O'' and scale factor kk'.

Hence, An enlargement with centre O and scale factor K followed by an enlargement with different centre O' and scale factor k' is equivalent to enlargement with the O" and scale factor KKK'. The centre of combined enlargement can be found by drawing.

An enlargement followed by another enlargement is equivalent to a new enlargement.

Combination of reflection and rotation

An object once reflected can further be rotated to get a new image. A reflection followed by a rotation is also a type of combination of two transformations.

1. Reflection in X-axis followed by a rotation about origin through 900.

Let R0 be the reflection in X-axis.

Then,R0: P' (x, -y)→ P"(y, x)

∴R0.Re: P(x, y) → P"(y, x) ...............................(i)

Again, let R be the reflection in the line y = x.

Then, R:P (x, y) → P"(y, x) ......................................................(ii)

So, reflection in the X-axis followed by a rotation about origin through 900 is equivalent to the reflection in the line y = x.

2. Reflection in Y-axis followed by a rotation about origin through 900.

Let Re be the reflection in Y-axis.

Then, Re: P(x, y)→ P'(-x, y).

LetR0 be the rotation about origin through 900.

Then,R0: P (x, y) → P" (-y, -x)

∴R0. Re: p (x, y) = P"(-y, -x) .........(i)

Again, let R be the reflection in the line y = -x.

Then, R: P(x, y) → P"(-y, -x) ............................(ii)

So, reflection in Y-axis followed by a rotation about origin through 900 is equivalent to the reflection in the line y = -x.

3. Reflection in the line y = x followed by a rotation through 900 about the origin.

Let Re be the reflection in te line y = x.

Then, Re: P (x, y)→ P'(y, x)

Let R0: P' (y, x)→ P" (-x, y) ....................(i)

Again, Let R be the reflection in the Y-axis.

Then, R:P (x, y) → P"(-x, y) .........................(ii)

Hence, reflection in the line y = x followed by a rotation about the origin through 900 is equivalent to the reflection in Y-axis.

Similarly, we ca establish the following results:

4. Reflection in X-axis followed by a rotation through - 900 about the origin is equivalent to the reflection in the line y = -x.

5. Reflection in Y-axis followed by a rotation through -900 about the origin is equivalent to the reflection in the line y = x.

6. Reflection in the line y = x followed by a rotation through -900 about the origin is equivalent to the reflection in X-axis.

Combination of rotation and reflection

A point or an object once rotated can further be reflected to get a new image. A rotation followed by a reflection is also a type of combination of transformation.

1. Rotation about origin through 900 followed by a reflection in the x-axis.

Let Ro be the rotation about origin through 900. Then,

Ro: P(x, y)→ P'(-y, x).

Let Re be the reflection in the x-axis.

Then, Re: P' (-y, x) → P"(-y, -x)

∴ Re.R0: P (x, y) → P" (-y, -x) .....................(i)

Again, Let R be the reflection in the line y = -x.

Then, R: P (x, y) →P"(-y, -x) .............................(ii)

Hence, rotation about origin through 90o followed by a reflection in X-axis is equivalent to the reflection in the line y = -x.

2. Rotation about origin through 900 followed by reflection in Y-axis.

Let Ro be the rotation about origin through 900.

Then, Ro: P (x, y) → P'(-y, x).

Let Re be the reflection in the y-axis.

Then, Re: P' (-y, x) → P"(y, x).

∴ Re.Ro: P (x, y) → P"(y, x) ........................(i)

Again, let R be the reflection in the line y = x.

Then, R: P(x, y)→ P" (y, x) .................(ii)

So, rotation about origin through 90o followed by the reflection in Y-axis is equivalent to a reflection in the line y = x.

3. Rotation about origin through 90o followed by reflection in the lie y = x

Let Ro be the rotation about origin through 900.

Then, Ro:P (x, y)→ P' (-y, x).

Let Re be the reflection in the line y = x.

Then,Re: P'(-y, x)→ P"(x, -y)

∴ Re.Ro: P(x,y)→ P"(x, -y) ............................................(i)

Again, let R be the reflection in X-axis.

Then, R:P (x, y)→ P"(x, -y) ...............................(ii)

So, rotation about origin through 900 followed by a reflection in the line y = x is equivalent to a reflection in X-axis.

As above, we can establish the following results:

4. A rotation about origin through - 90o followed by a reflection in X-axis is equivalent to a reflection in the line y = x.

5. A rotation about origin through -90o followed by a reflection in Y-axis is equivalent to a reflection in the line y = -x.

6. A rotation about origin through -90o followed by a reflection in the line y = x is equivalent to a reflection in the y-axis.

Combination of Reflection and translation

A point or an object once reflected can further be translated. Similarly, a point or an object once translated can further be reflected.

Let r be the reflection in X-axis and T =(\(\frac{a}{b}\)) be a translation.

Then, R:P (x, y)→ P'(x, -y) and

T: P' (x, -y)→ P"(x + a, -y + b).

ToR: P (x, y)→ P" (x + a, -y + b)

So, P"(x + a, -y + b) is the image of P (x, y) under the reflection in X-axis followed by translation T.

Again,T:P (x, y)→ P'(x + a, y + b) and

R:P' (x + a, y + b)→ P' (x + a, -y - b)

RoT: P (x, y) → P"(x + a, -y -b)

So, P" (x + a, -y - b) is image of P(x, y) under translation T followed by reflection R.

Combination of rotation and translation

A point or object once rotated can further be translated. Similarly, a point or an object once translated can further be rotated.

Let R be the rotation through 900 about the origin and T = \(\begin{bmatrix}a\\b\\ \end{bmatrix}\) be a translation.

Then, R: P (x, y)→ P' (-y, x).

∴ T: P' (-y, x)→ P" (-y + a, x + b)

ToR: P(x, y) → P" (-y -b, x + a)

So, P' (-y -b, x + a) is image of P(x, y) under reflection R followed by translation T.

Again, T: P (x, y)→P' (x + a, y + b) and

R: P' (x + a, y + b)→ P" (-y -b, x + a)

∴ RoT: P (x, y)→ P"(-y -b, x + a).

So, P" (-y - b, x + a) is the image of P (x, y) under translation T followed by rotation R.

Combination of Reflection and Enlargement

Let R be the reflection in X-axis and E [O, k] be the enlargement with centre O and scale factor k.

Then, R: P (x, y) → P'(x, -y) and

E:P' (x, -y) → P' (kx, -ky).

∴ EoR: P (x, y) → P'' (kx, -ky)

So, P" (kx, -ky) is image of p (x, y) under reflection r followed by enlargement E.

Again, E: P(x, y) → P'(kx, ky) and

R: P'(kx, ky) → P" (kx, -ky)

∴ RoE: P(x, y) → P"(kx, - ky).

So, P" (kx, -ky) is an image of p (x, y) under enlargement E followed by reflection R.

Combination of rotation and enlargement

Let R be the rotation through 900 about origin and E[O, k] be the enlargement with centre O and scale factor k.

Then, R:P(x, y) → P'(-y, x) and

E:P'(-y, x)→ P"(-ky, kx)

∴EoR:P(x, y)→ P"(-ky, kx)

So, P" (-ky, kx) is an image of P (x, y) under rotation R followed by enlargement E.

Again, e:P(x, y)→ P' (kx, ky) and

R:P'(kx, ky)→ P"(-ky, kx)

RoE: p(x, y)→ p"(-ky, kx)

So, P"(-ky, kx)is an image of P(x, y) under enlargement E followed by rotation R.

Combination of translation and Enlargement

Let T =\(\begin{bmatrix}a\\b\\ \end{bmatrix}\) be a translation and E [o, k] be an enlargement with centre O and scale factor k.

Then, T:P(x, y)→ P'(x + a, y + b)

E:P'(x + a, y + b)→ P"(kx + ka, ky + kb)

∴ EoT: P(x, y)→ P"(kx + ka, ky + kb)

So, P" (kx + ka, Ky + kb) is image of P (x, y) under translation T followed by enlargement E.

Again, E:P(x, y)→ P'(kx, ky) and

T:P'(kx, ky) → P"(kx + a, ky + b)

∴ToE: P(x, y)→ P" (kx + a, ky + b)

So, P"(kx + a, ky + b) is image of P(x, y) under enlargement e followed by translation T.

Transformations Object point Image point
Reflection in X-axis (y = 0) P(x, y) P'(x, -y)
Reflection in Y-axis(x = 0) P(x, y) P'(-x, y)
Reflection in the line y = x P(x, y) P'(y, x)
Reflection in the line y = -x P(x, y) P'(-y, -x)
Reflection in the line x = k(parallel to Y-axis) P(x, y) P'(2k - x, y)
Reflection in line y = k (parallel to X-axis) P(x, y) P'(x, 2k - y)
Rotation about origin through 90o P(x, y) P'(-y, x)
Rotation about origin through -900 P(x, y) P'(y, -x)
Rotation about origin through 180o P(x, y) P'(-x, -y)
TranslationT = \(\begin{bmatrix}a\\b\\ \end{bmatrix}\) P (x, y) P'(x + a, Y + b)
enlargement with centre origin and scale factor k, E [(o,o),k] P(x, y) P'(kx, ky)
Enlargement with centre (a, b) and scale factor k, E [(a, b), k] P(x, y) P'(kx - ka + a, ky - kb + b)

Transformation formula Matrix
Reflection on x-axis (x , Y)→(x , Y)

\begin{pmatrix}1 & 0 \\ 0 & -1 \\ \end{pmatrix}

Reflection on y - axis (x , y)→(-x ,y) \begin{pmatrix} -1 & 0 \\ 0 & 1 \\ \end{pmatrix}

 

Here,

T1 = \(\begin {pmatrix} -2\\ 1\\ \end{pmatrix}\), T2 = \(\begin {pmatrix} 0\\ 2\\ \end{pmatrix}\)

T2T1 =\(\begin {pmatrix} -2\\ 1\\ \end{pmatrix}\) +\(\begin {pmatrix} 0\\ 2\\ \end{pmatrix}\) =\(\begin {pmatrix} -2\\ 3\\ \end{pmatrix}\)

Under the combined translation T2T1 =\(\begin {pmatrix} -2\\ 3\\ \end{pmatrix}\)translation (a b)

translation (a b)

The co-ordinates of \(\triangle\)PQR are P(1, 4), Q(4, 1) and R(7, 5) when \(\triangle\)PQR reflection on the x - axis then the vertices of image are as follows:

reflection on y- axis
reflection on y- axis

Again,

When \(\triangle\)P'Q'R' reflection on the line x = y the vertices of the images are as follows:

reflection on the line y = x
reflection on the line y = x

The co-ordinates of the \(\triangle\)PQR, \(\triangle\)P'Q'R' and \(\triangle\)P"Q"R" are as shown in the graph paper as below:

figure
figure

The co-ordinates of \(\triangle\)ABC are A(1, 2), B(4, -1) and C(2, 5) when \(\triangle\)ABC reflection in the line x = 5 then the vertices of the image are as follows:

reflection on x = h
reflection on x = h

Again,

When \(\triangle\)A'B'C' reflection on the line y = -2, then:

reflection on the line y = k
reflection on the line y = k

The co-ordinates of the \(\triangle\)ABC, \(\triangle\)A'B'C' and \(\triangle\)A"B"C" are shown in the graph paper as below:

The single transformation as half turn about (5, -2).

figure
figure

The image of the point P(x, y) rotated half turn about (a, b)

rotation about (a, b)
rotation about (a, b)

The image of the point P(x, y) rotated 90º+ about (a, b) is:

rotation about (a, b)
rotation about (a, b)

∴ The final image of \(\triangle\)MNP, \(\triangle\)M'N'P' and \(\triangle\)M"N"P" in graph paper is:

figure
figure

The co-ordinates of \(\triangle\)PQR areP(-4, 6), Q(2, 8) and R(6, 2). When \(\triangle\)PQR is enlarged on E[(2, 3), -2] then the vertices of the images are as follows:

E[(a,b), k]
E[(a,b), k]

Again,

When \(\triangle\)P'Q'R' reflection on the line y = x then, the vertices of the images are as follows:

reflection y = x
reflection y = x

The \(\triangle\)PQR, \(\triangle\)P'Q'R' and \(\triangle\)P"Q"R" on graph paper as follows:

figure
figure
0%
  • If r1 represents the reflection on X-axis and r2 represents the reflection on y-axis then translate the point  (3 -2) by r1 or r.

    (-3 , -2)


    (3 , -2)


    (-3 , 2)


    2


  • If r1 represents the reflection on X-axis and r2 represents  the reflection on y-axis then find the image of the point (1 , 5) under the combined transformation r1.r2 .

    (1  , 5)


    (-1 , -5)


    (2 , 2)


    (-1 , 5)


  • If F be the reflection on line y = x and G be the reflection on line x = 0 then state what does GoF represents? If a point P is transformed by the above single transformation to P '(-2 , 3) , find the co-ordinates  of point 'P'.

    Ro[700 , 0] ; P(2 , 2)


    Ro[900 , 0] ; P(3 , 2)


    Ro[3600] ; P(2 , 3)


    Ro[1800 , 0] ; P(-3 , -2)


  • R1 and R2 denote the reflections on x = -y and x = 4 respectively. What point would have the image (2 , -5) under the combined R1 or R2 ?

    (2 , 3)


    -2


    (3 , -2)


    (3 , 2)


  • Point  (4  , -3) is reflected in the line x = 0 at first and then the image s formed is reflected in the line y = k so that the final image (-4 , 9) is obtained. Find the value of k.

    -6


    4


    7


    6


  • Point (8 , 10) is reflected in th line x = 0 at first and then image so formed is reflected in the line y - m = 0 so that the final image (-8 , 6) is obtained. Find the value of m.

    4


    -6


    -4


    8


  • The vertices of ΔABC are A (2,1) , B(-1 , 4) and C (-2 , -2). Find the co-ordinates of the vertices of the image of ΔABC under the transformation of T1 or T2 where T1 = ( (frac{1}{2}) ) and T2 = ( (frac{-3}{1}) )

    ;i:1;s:46:

    A' (8 , 8) , B' (6 , 6) , C
    (4 , -1)


    A' (0 , 4) , B' (-3 , 7) , C

  • Point (3 , 2) is reflected on the line y =x . The image so obtained is rotated about O through +90(^o). Find the coordinates of the image.

    (-3 , 0)


    (-3 , 2)


    (8 , 3)


    (1 , 4)


  • Find the coordinates of the image of the point (-5 , 7) , when it is first reflected on the line y = -x and then the image so formed is rotated about the origin O through an angle of +180(^o).

    (9 , 4)


    (9 , 6)


    (7 , 5)


    (7 , -5)


  • Determine the coordinates of the image of a point (3 , 7) when it is first reflected on the Y-axis and then rotated through an angle  +90(^o) about the origin. Also write down a single transformation which denotes both of these transformation.

    (7 , 3) ; Ref' (y = x)


    (-7 , -3) ; Ref' (y = -x)


    (7 , 3) ; Ref' (y = y)


    (7 , 3) ; Ref' (y = x)


  • The image formed by reflecting the point (3 , 4) n the Y-axis is rotated about origin O(0 , 0) thrpugh +90(^o) , find the coordinates of this image.

    (4 , 3)


    ;i:1;s:17:

    P

    P

  • A point A(-2 , 3) is reflected on Y-axis and the image so obtained is rotated about origin through -90(^0). Find the coordinates of final image.

    (3 , 2)


    ;i:1;s:16:

    A

    A

  • A point A(-2 , 3) is reflected on Y-axis and the image so obtained is rotated about origin through -90(^0). Find the coordinates of final image.

    A
    ;i:1;s:16:
    (3 , 2)


    A

  • Point (4,5) is rotated about the origin O through + 90(^0) and the image so obtained is reflected on the Y-axis. Find the coordinates of the image.

    (5, 4)


    (4,5)


    (3,2)


    (1 , 2)


  • Find the coordinates of the image of a point (4,5) when it is first rotated by +90 (^0) about the origin 0 and then reflected on the X-axis. Also write down the single transformation which represents both of these two transformations.

    (-5  , 8) , reflection in x = y


    (-5  , -4) , reflection in x = -y


    (-15  , 89) , reflection in -x = - y


    (5  , -3) , reflection in x = - y


  • Find the coordinates of the image of a point (3 , 20 when it is first rotated by + 1800 about the origin O and then reflected in the Y-axis.

    P
    (3 , 2)


    ;i:1;s:17:

    P

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Discussions about this note

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Dewaki

L1 and L2 are two axes of reflection intersecting at origin O inclined with each other at angle 45 degree.Find image of the point (-5,-3) and (4,-2) by the reflection about the line L2 followed by reflection about linr L1

triangle pqr of vertices p(-2,1),q(-4,2)and r(-6,4) is reflected first on line cd and then on line ab combined transformation if angle coa=45 degree.show both triangles on same graph paper.

yamini.

what is the image of C(-1,5) when it is reflected about y = -x followed by the reflection about y=2 line?state the single transformation equivalent to the above combined transformation.