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Note on Standard Deviation

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Standard deviation is the position square root of the arithmetic mean of the squares of the deviations of the given observation from their arithmetic mean.

Amongst all the methods of finding out dispersion, the standard deviation is regarded as the best. It is free from those defects with which the earlier methods (range, quartile deviation and mean deviation) suffer. Its value is based upon each and every item of the series and it also take into account algebraic signs. Standard deviation is also known as 'Root-Mean-Square Deviation' because it is the square root of the arithmetic mean of the square of the deviations. It is denoted by the Greek letter \(\sigma\) (known as Sigma).

  1. While computing mean deviation, algebraic signs are ignored, whereas while calculating standard deviation, algebraic signs are taken into account.
  2. The mean deviation can be computed either from mean, median or mode, whereas standard deviation is always computed from arithmetic mean.

Calculation of Standard Deviation

formulas
formulas
Individual Series

(1) Direct Method or Actual Mean Method:

Let X1, X2, X3, .......................... Xn be the N-variate and \(\overline{X}\) be the arithmetic mean.

Define: x = X - \(\overline{X}\) = deviation taken from actual mean.

Then, standard deviation is given by the following formula:

\begin{align*} \sigma = \sqrt {\frac {\sum{x^2}}N}\\ \end{align*}

(2) Short-cut Method of Assumed Mean Method:

Let X1, X2, X3, ..........................Xn be the N-variate values and A be the assumed mean.

Define: d = X - A = deviation taken from assumed mean.

Then, standard deviation is defined by the following formula:

\begin{align*} \sigma &= \sqrt {\frac {\sum{d^2}}N - (\frac {\sum {d}}N)^2}\\ \end{align*}

This method is suitable when the actual mean is in fraction (or decimal).

Discrete Series

Let X1, X2, X3, ........................ Xn be the variable values and f1, f2, f3, ....................... fn is their frequencies.

Let, \(\overline{X}\) and A be the actual mean and assumed mean respectively. Then the standard deviation is defined by the following formulae:

(1) Direct Method or Actual Mean Method:

If x = X - \(\overline{X}\), then \(\sigma\) = \(\sqrt {\frac {\sum {fx^2}}N}\)

(2) Short cut Method or Assumed Mean Method:

If d = X - A, then \(\sigma\) = \(\sqrt {\frac {\sum{fd^2}}N - (\frac {\sum {fd}}N)^2}\)

(3) Step-Deviation Method:

If d' = \(\frac {X - A}h\), where h is common factor, then \(\sigma\) = \(\sqrt {\frac {\sum {fd'^2}}N - (\frac {\sum {fd'}}N)^2}\)× h

Continuous Series

Let X1, X2, X3, ............................. Xn be the mid-values of the classes and f1, f2, f3, ....................... fn be their frequencies.

Let \(\overline{X}\) and A be the actual mean and assumed mean. Then, the standard deviation is defined by the following formulae:

(1) Direct Method:

If x = X - \(\overline{X}\), then \(\sigma\) = \(\sqrt {\frac {\sum {fx^2}}N}\)

(2) Short-cut Method:

If d = X - A, then \(\sigma\) = \(\sqrt {\frac {\sum {fd^2}}N - ({\frac {\sum {fd}}{N}})^2}\)

(3) Step Deviation Method:

If d' = \(\frac {X - A}h\), h = class size or common factor, then \(\sigma\) = \(\sqrt {\frac {\sum {fd'^2}}N - (\frac {\sum {fd'}}N)^2}\)× h

Coefficient of standard deviation and coefficient of variation

Standard deviation is the absolute measure of dispersion based on the standard deviation is known as the coefficient of standard deviation. Thus,

Coefficient of S.D. = \(\frac {S.D.}{Mean}\)

Also, the coefficient of standard deviation multiplied by 100 is known as the coefficient of variation (C.V.). Thus,

Coefficient of Variation (C.V.) = \(\frac {S.D.}{Mean}\)× 100

Merits and Demerits of Standard Deviation

Merits

  1. The value of standard deviation is based on each and every item of the data.
  2. It is free from those defects with which other methods like range, quartile deviation, mean deviation suffer.
  3. It is less affected by fluctuations of sampling.

Demerits

  1. As compared to the measure, it is somewhat more difficult to understand and compute.
  2. Its value is unduly affected by extreme observations.

  • The smaller value of the coefficient of variation indicates the data is consistency or uniform.
  • the greater value of the coefficient of variation indicates the data is not consistency or uniform.
  • In the comparative study of two data, the data with the smaller value of a coefficient of variation is considered as good or uniform.
  • The maximum value of a coefficient of variation is 1 or 100%.
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Very Short Questions

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  • Find the standard deviation of the given data:

    20, 25, 28, 30, 40, 35

    6.05


    6.5


    7.5


    3.15


  • Calculate standard deviation and its coefficient:

     

    X 140 142 150 147 145
    f 4 8 9 3 2

    2.23, 0.096


    4.29, 0.039


    6.15, 0.056


    3.95, 0.027


  • Find the standard deviation from the following data:

    Mid Value 2.5 7.5 12.5 17.5 22.5 27.5
    f 3 2 7 9 1 6

    6.26


    7.63


    8.25


    6.73


  • Find the standard deviation of the data:

    X 92 93 97 98 102 104 109
    f 3 2 3 2 6 3 3

    5.395


    6.652


    4.369


    7.325


  • Find the standard deviation:

    X 15 25 30 25 40 45
    f 1 5 10 12 8 4

    5.6


    7.5


    5.9


    6.6


  • Find the standard deviation:

    X 12 14 16 18 20 25
    f 6 7 10 15 10 2

    3.02


    5.52


    2.01


    4.05


  • Find the standard deviation:

    x = 20, 25, 28, 30, 40, 35.

    42.22


    41.56


    47.32


    45.55


  • Calculate the standard deviation:

    Marks 0-10 10-20 20-30 30-40 40-50
    No. of student 15 17 12 9 12

    15.7


    13.3


    12.1


    14.2


  • Find the standard deviation:

    Marks 0-6 0-12 0-18 0-24 0-30
    no. of student 4 7 12 18 20

    6.63


    8.25


    7.70


    9.13


  • Find the standard deviation:

    Marks  30-40 40-50 50-60 60-70 70-80
    No. of student 2 3 6 5 4

    12.29


    9.93


    11.33


    13.25


  • Find the standard deviation:

    X 0-10 10-20 20-30 30-40 40-50 50-60
    f 1 5 8 10 4 2

    13.09


    11.03


    10.36


    12.02


  • Find the standard deviation:

    X 0-10 10-20 20-30 30-40 40-50
    f 5 4 4 6 1

    13.39


    11.33


    12.69


    10.05


  • Find the standard deviation:

    Marks 10 20 30 40 50
    No. of student 8 12 15 9 6

    8.32


    9.05


    11.23


    10.05


  • Find the standard deviation and its coefficient:

    C . I. 0-10 10-20 20-30 30-40 40-50
    Frequency 4 6 5 3 2

    12.36


    11.25


    10.02


    13.39


  • Find the standard deviation and its coefficient:

    Class 10 20 30 40 50
    Frequency 2 4 3 7 4

    13.75


    11.75


    10.32


    12.75


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smriti khanal

if the median of the following data is 24,find the standard deviationmarks obtained:- 0-10 10-20 20-30 30-40 40-50no of students:- 9 ,21,x,15,10


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