Solution:

S

A(2,-2)\(\rightarrow\)A’(-2,-2)

B(5,3)\(\rightarrow\)B’(-5,3)

C(1,4)\(\rightarrow\)C’(-1,4)

So, the coordinates of the vertices of image \(\triangle\)A’B’C’ are A(-2,-2), B(-5,3) and C(-1,4).

Solution:

S

A(-2,3)\(\rightarrow\)A’(-2,-2)

B(2,1)\(\rightarrow\)B’(2,-1)

C(4,4)\(\rightarrow\)C’(4,-4)

So, the coordinates of the vertices of image \(\triangle\)A’B’C’ are A(-2,-3), B(2,-1) and C(4,-4).