Solution:

A(2,-2)$$\rightarrow$$A’(-2,-2)

B(5,3)$$\rightarrow$$B’(-5,3)

C(1,4)$$\rightarrow$$C’(-1,4)

So, the coordinates of the vertices of image $$\triangle$$A’B’C’ are A(-2,-2), B(-5,3) and C(-1,4).

Solution:

A(-2,3)$$\rightarrow$$A’(-2,-2)

B(2,1)$$\rightarrow$$B’(2,-1)

C(4,4)$$\rightarrow$$C’(4,-4)

So, the coordinates of the vertices of image $$\triangle$$A’B’C’ are A(-2,-3), B(2,-1) and C(4,-4).