Subject: Compulsory Maths
All the Triangle , Circle , Square, and Rectangle are plan figure . The total length of the boundary lines of plan figure is called its perimeter.Perimeter of Triangles :
The sum of the length of its three sides is known as a perimeter of triangles . Therefore,
\(\therefore\) Perimeter of \(\triangle DEF\) =DE + EF+ FD = a+b+c
The half of its perimeter is known as semi -perimeter of triangle . It is denoted by the letter 's'.
\(\therefore\) Semi -perimeter of \(\triangle\)DEF= \(\frac{a+b+c}{2}\)
The opposite sides of rectangle are always equal . So , the lengths = EF=GH=l
the breadths =FH=EG=b
The perimeter of the rectangles EFGH =EF+FG+GH+HG
=l+b+l+b=2l+2b
=2(l+b)
\(\therefore\)Perimeter of rectangle = 2(l+b)
In the case of Square , its perimeter =2(l+l)
=2x2l=4l
At first draw three circles with radii 2cm , 3cm, and 4cm, and place the pieces of strings along the circumference of each separately .
Then start measuring the length of each string separately with the help of scale . Then, find the ratios of the length of the circumference of each circle to its diameter . Now , you all will find the ratio \(\frac{circumference}{diameter}\) is almost the same for every circle. The constant ratio is represented by Greek letter 'π' (pie). So , the circumference of circle iscand its diameter bed,
Now , \(\frac{circumfernce }{diameter})=π
or, \(\frac{c}{d})=π
or, c=πd
Diameter of circle (d) =2xradius (r).
So, circumference or the perimeter of circle (c) =2πr
The perimeter of circle =πd or2πr
If the perimeter of a rectangular field of length 25m is 86m, find its breadth.
Solution:
Here,
the length of the field (l) = 25 m
the perimeter of the field = 86 m
Now,
the perimeter of the rectangular field = 86 m
or, 2(l + b) = 86 m
or, 25 + b = \(\frac{86}{2}\) m
or, 25 + b = 43 m
or, b = (43 - 25) m
or, b = 18 m
∴ the required breadth of the field is 18 m
The radius of a circular ground is 35m, find the length of wire required to fence it with 4 rounds. Also find the cost of fencing at Rs 10 per meter.
Solution:
Here,
the radius of the circular ground (r) = 35m
its perimeter = 2πr
= 2 × \(\frac{22}{7}\) × 35 m
= 2 × 22 × 5
= 220 m
∴ The required length of wire = 4 × 220m
= 880 m
Again,
the required cost of fencing = 880 × Rs 10
= Rs 8800
If the required length of wire is 880 m and the per meter costs Rs.10. Find the total cost.
Solution:
length of wire = 880 m
per meter cost of wire = Rs. 10
Now, Total cost of wire = 880 × 10 = Rs. 8800 ans.
What is perimeter? Give the examples of plane figures.
The total length of the boundary lines in the plane figure is called the perimeter. The examples of plane figures are triangle, rectangle, square, circle, etc.
Mention the formula of a perimeter of triangles, perimeter of rectangles and perimeter of circles.
The formulas are as following:
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