Subject: Compulsory Maths
The amount of turn between two straight lines that have a common endpoint that is a vertex.
Different Pairs of angles
Pairs of angles made by a transversal with lines
In the given figure, AB and CD and two parallel lines (AB//CD). PQ is the transversal that intersects AB at R and CD at S.
If x° and (x+10)° are a pair of complementary angles, find them.
Solution:
Here, x° + (x+10)° = 90° [The sum of a pair of complementary angles]
or, 2x° = 90° - 10°
or, x° = \(\frac{80°}{2}\) = 40°
\(\therefore\) x° = 40° and (x+10)° = 40° + 10° = 50°
A pair of supplementary angles are in the ratio 3:2, find them.
Solution:
Let the required supplementary angles be 3x° and 2x°.
\(\therefore\) 3x° + 2x° = 180° [The sum of a pair of supplementary angles]
or, 5x° = 180°
x° = \(\frac{180°}{5}\) = 36°
\(\therefore\) 3x° = 3 × 36° = 108°
2x° = 2 × 36° = 72°
In the adjoining figure, find the sizes of unknown angles.
Solution:
Here, x° + 2x° + 3x° = 180° [Being the sum a straight angle]
or, 6x° = 180°
or, x° = \(\frac{180°}{6}\) = 30°
\(\therefore\) x° = 30°, 2x° = 2×30° = 60° and 3x° = 3×30° = 90°
Again, a° = x° = 30°, b = 2x° = 60° and c° = 3x° = 90° [Each pair is vertically opposite angles]
Find the sizes of unknown angles of the following figure:
a)
Solution:
w = 110° [Being vertically opposite angles]
x = w = 110° [Being alternate angles]
y = x = 110° [Being vertically opposite angles]
y + z = 180° [Being the sum of a pair of co-interior angles]
or, 110 + z = 180°
or, z = 180° - 110° = 70°
So, w = x= y = 110° and z = 70°
Mention the different pairs of angles.
The different pairs of angles are:
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