Subject: Compulsory Maths
A fraction is a number which is usually expressed in the form of \(\frac{a}{b}\). For examples ( \(\frac{3}{4}\), \(\frac{5}{3}\), \(\frac{9}{7}\), etc.)
Comparison of fraction
A fraction can be compared to their likes and unlike terms. We can compare like fractions by comparing their numerators and to compare unlike fractions, we should convert them into like fractions. By comparing those like fractions, as a result, we can find greater and the smaller fraction. For example, Let's compare \(\frac{5}{3}\) and \(\frac{7}{4}\)
Here, the L.C.M of denominators 3 and 4 = 3×4 = 12
Now, \(\frac{5}{3}\) = \(\frac{5×4}{3×4}\) = \(\frac{20}{12}\)
And, \(\frac{7×3}{4×3}\) = \(\frac{21}{12}\)
Here, \(\frac{21}{12}\) > \(\frac{20}{12}\), So, \(\frac{7}{3}\) > \(\frac{4}{3}\)
Addition and Substraction of Fraction
If the like fraction is given, we can add or substract them just by adding or substracting their numenator. For example, \(\frac{5}{6}\) + \(\frac{7}{6}\) = \(\frac{12}{6}\) = 2
\(\frac{10}{7}\) - \(\frac{9}{7}\) = \(\frac{10 - 9}{7}\) = \(\frac{1}{7}\) ans.
In case of unlike fraction, at first we should convert them into like fractions with the least common denominator, then we add or substract their numenator. For example,
or,\(\frac{4}{5}\) - \(\frac{3}{7}\) = \(\frac{4 × 7}{5 × 7}\) - \(\frac{3 × 5}{7 × 5}\)
= \(\frac{21}{35}\) - \(\frac{15}{35}\)
= \(\frac{21 -15}{35}\)
= \(\frac{6}{35}\) ans.
Multiplication of fraction
Multiplication of fraction can be done by the product of a whole number and a fraction as well as product of a two fraction. For example 3× \(\frac{4}{3}\)
\(\frac{3}{1}\) × \(\frac{4}{3}\) = \(\frac{12}{3}\) =4
\(\frac{1}{3}\) × \(\frac{6}{5}\) = \(\frac{1×6}{3×5}\) = \(\frac{6}{15}\) = \(\frac{2}{5}\) ans.
Division of fraction
To divide a whole number by a fraction, we should multiply the whole number by the reciprocal of the fraction. For example,
4÷ \(\frac{1}{6}\) = 4× \(\frac{1}{6}\) = \(\frac{4}{6}\) = \(\frac{2}{3}\) ans.
Simplify : 2\(\frac{3}{4}\)+1\(\frac{5}{8}\)-3\(\frac{1}{3}\).
soln:
2\(\frac{3}{4}\)+1\(\frac{5}{8}\)-3\(\frac{1}{3}\)
= \(\frac{11}{4}\)+\(\frac{13}{8}\)-\(\frac{10}{3}\)
=\(\frac{11\times6+13\times3-10\times8}{24}\)
=\(\frac{66+39-80}{24}\)
=\(\frac{105-80}{24}\)
=\(\frac{25}{24}\)
=1\(\frac{1}{24}\)
Add : \(\frac{2}{9}\)+\(\frac{4}{9}\)
\(\frac{2}{9}\)+\(\frac{4}{9}\)
=\(\frac{2+4}{9}\)
=\(\frac{6}{9}\)
=\(\frac{2}{3}\)
Subtraction : \(\frac{3}{5}\)-\(\frac{2}{7}\)
soln:
\(\frac{3}{5}\)-\(\frac{2}{7}\)
=\(\frac{3\times7-2\times5}{35}\)
=\(\frac{21-10}{35}\)
=\(\frac{11}{35}\)
Addation ; \(\frac{3}{5}\) -\(\frac{2}{7}\)
Soln:
\(\frac{3}{5}\)-\(\frac{2}{7}\)
=\(\frac{3\times7}{5\times7}\) -\(\frac{2\times5}{7\times5}\)
=\(\frac{21}{35}\) - \(\frac{10}{35}\)
=\(\frac{21-10}{35}\)
=\(\frac{11}{35}\)
Find the value of \(\frac{3}{5}\) of Rs 750.
Soln:
\(\frac{3}{5}\) of Rs 750=\(\frac{3}{5}\) x Rs 750
=Rs450.
If \(\frac{2}{7}\) of a sum is Rs. 120, find the sum.
Solution:
Let the required sum be x.
Now, \(\frac{2}{7}\) of x = Rs. 120
or, \(\frac{2}{7}\) × x = Rs. 120
or, 2x = 7 × Rs. 120
or, x = \(\frac{7 × Rs. 120}{2}\)
= Rs. 420
So the required sum is Rs. 420.
A man had some milk. When he sold \(\frac{3}{4}\) parts of the quantity of milk, 15 l was left. How much milk did he have in the beginning?
Solution:
Let, he had x l of milk in the begining.
Remaining parts of the quantity of milk = 1 - \(\frac{3}{4}\) = \(\frac{1}{4}\) part.
Now, \(\frac{1}{4}\) of x = 15 l
or, \(\frac{1}{4}\) × x = 15 l
or, x = 4 × 15 l = 60 l
So, he had 60 l of milk in the begining.
Kamala can do \(\frac{1}{12}\) part a piece of work in 1 day. She worked for 3 days and left. The remaining parts of the work is done by Reeta. How much work is done by Reeta?
Solution:
In 1 day, Kamala can do \(\frac{1}{12}\) part of a piece of work.
In 3 days, Kamala can do 3 × \(\frac{1}{12}\) part of work = \(\frac{1}{4}\) parts of a piece of work
Now, the remaining parts of the work done by Reeta = (1-\(\frac{1}{4}\)) = \(\frac{3}{4}\) parts.
So, \(\frac{3}{4}\) parts of the work is done by Reeta.
© 2019-20 Kullabs. All Rights Reserved.